In this article, we will discuss how to calculate power in DC parallel circuits. We will start by reviewing the basics of parallel circuits, then we will discuss the formula for calculating power in a parallel circuit. Finally, we will provide some examples of how to calculate power in parallel circuits.

## Basics of Parallel Circuits A parallel circuit is a circuit in which two or more components are connected in parallel. This means that the components are all connected to the same voltage source, but they are not connected to each other. In a parallel circuit, the total current is the sum of the currents through each individual component.

## Formula for Calculating Power in a Parallel Circuit The formula for calculating power in a parallel circuit is: ``` P = I^2R ``` where: *

### P

is the power in watts *### I

is the current in amps *### R

is the resistance in ohms## Examples of Calculating Power in Parallel Circuits Let's look at some examples of how to calculate power in parallel circuits.

### Example 1:

Consider the following parallel circuit:

In this circuit, the voltage source is 12 volts, and the resistors are 2 ohms, 4 ohms, and 6 ohms.

To calculate the total current in the circuit, we can use the formula: ``` I = V/R ``` In this case, the total current is: ``` I = 12 V / (2 ohms + 4 ohms + 6 ohms) = 2 amps ```

To calculate the power dissipated by each resistor, we can use the formula: ``` P = I^2R ``` In this case, the power dissipated by the 2 ohm resistor is: ``` P = (2 amps)^2 * 2 ohms = 8 watts ``` The power dissipated by the 4 ohm resistor is: ``` P = (2 amps)^2 * 4 ohms = 16 watts ``` And the power dissipated by the 6 ohm resistor is: ``` P = (2 amps)^2 * 6 ohms = 24 watts ```

So, the total power dissipated in the circuit is: ``` P = 8 watts + 16 watts + 24 watts = 48 watts ```

### Example 2:

Now, let's consider a more complicated parallel circuit:

In this circuit, the voltage source is 12 volts, and the resistors are 2 ohms, 4 ohms, 6 ohms, and 8 ohms.

To calculate the total current in the circuit, we can use the formula: ``` I = V/R ``` In this case, the total current is: ``` I = 12 V / (2 ohms + 4 ohms + 6 ohms + 8 ohms) = 1 amp ```

To calculate the power dissipated by each resistor, we can use the formula: ``` P = I^2R ``` In this case, the power dissipated by the 2 ohm resistor is: ``` P = (1 amp)^2 * 2 ohms = 2 watts ``` The power dissipated by the 4 ohm resistor is: ``` P = (1 amp)^2 * 4 ohms = 4 watts ``` And the power dissipated by the 6 ohm resistor is: ``` P = (1 amp)^2 * 6 ohms = 6 watts ``` The power dissipated by the 8 ohm resistor is: ``` P = (1 amp)^2 * 8 ohms = 8 watts ```

So, the total power dissipated in the circuit is: ``` P = 2 watts + 4 watts + 6 watts + 8 watts = 20 watts

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