Parallel Circuit Sample Problems With Solutions

In this article, we will provide you with some parallel circuit sample problems with solutions. These problems will help you to understand how parallel circuits work and how to solve problems involving them. ### Parallel Circuit Problem 1

Problem:

A parallel circuit has two resistors, R1 and R2, connected to a battery. The resistance of R1 is 10 ohms and the resistance of R2 is 20 ohms. The battery has a voltage of 12 volts. What is the total resistance of the circuit?

Solution:

The total resistance of a parallel circuit is given by the following formula: ``` Rt = 1 / (1 / R1 + 1 / R2) ``` In this case, the total resistance is: ``` Rt = 1 / (1 / 10 + 1 / 20) = 6 ohms ``` ### Parallel Circuit Problem 2

Problem:

A parallel circuit has three resistors, R1, R2, and R3, connected to a battery. The resistance of R1 is 10 ohms, the resistance of R2 is 20 ohms, and the resistance of R3 is 30 ohms. The battery has a voltage of 12 volts. What is the current through each resistor?

Solution:

The current through each resistor in a parallel circuit is the same. The total current in the circuit can be found by using the following formula: ``` I = V / Rt ``` In this case, the total current is: ``` I = 12 V / 6 ohms = 2 amps ``` The current through each resistor is therefore: ``` I1 = 2 amps I2 = 2 amps I3 = 2 amps ``` ### Parallel Circuit Problem 3

Problem:

A parallel circuit has four resistors, R1, R2, R3, and R4, connected to a battery. The resistance of R1 is 10 ohms, the resistance of R2 is 20 ohms, the resistance of R3 is 30 ohms, and the resistance of R4 is 40 ohms. The battery has a voltage of 12 volts. What is the power dissipated by each resistor?

Solution:

The power dissipated by a resistor in a parallel circuit is given by the following formula: ``` P = I2R ``` In this case, the current through each resistor is the same as in the previous problem, so the power dissipated by each resistor is: ``` P1 = (2 amps)2 * 10 ohms = 40 watts P2 = (2 amps)2 * 20 ohms = 80 watts P3 = (2 amps)2 * 30 ohms = 120 watts P4 = (2 amps)2 * 40 ohms = 160 watts ``` ### Parallel Circuit Problem 4

Problem:

A parallel circuit has five resistors, R1, R2, R3, R4, and R5, connected to a battery. The resistance of R1 is 10 ohms, the resistance of R2 is 20 ohms, the resistance of R3 is 30 ohms, the resistance of R4 is 40 ohms, and the resistance of R5 is 50 ohms. The battery has a voltage of 12 volts. What is the voltage drop across each resistor?

Solution:

The voltage drop across each resistor in a parallel circuit is the same. The total voltage drop across the circuit can be found by using the following formula: ``` V = IRt ``` In this case, the total voltage drop is: ``` V = 12 V * 6 ohms = 72 volts ``` The voltage drop across each resistor is therefore: ``` V1 = 72 volts V2 = 72 volts V3 = 72 volts V4 = 72 volts V5 = 72 volts ``` ### Parallel Circuit Problem 5

Problem:

A parallel circuit has six resistors, R1, R2, R3, R4, R5, and R6, connected to a battery. The resistance of R1 is 10 ohms, the resistance of R2 is 20 ohms, the resistance of R3 is 30 ohms, the resistance of R4 is 40 ohms, the resistance of R5 is 50 ohms, and the resistance of R6 is 60 ohms. The battery has a

Solved Styles Series Parallel Circuits Name Date Objectives Chegg Com